What we know is MV⊙=4.83 and LWD=1010L⊙.
To solve, we can revisit week 5 to solve this problem. We know that absolute magnitude is related to luminosity: MWD−M⊙=−2.5log(LWDL⊙)
So MWD=−2.5log(1010L⊙L⊙)+M⊙
MWD=−2.5log(1010)+8.83=−25+4.83=−20.17
Now that we have a (rather large) absolute magnitude and a limit on our ability to detect apparent magnitudes, we can find distance. m−M=5log(d)−5
d=10m−M+55
d=1021+20.17+55=1.7×109pc
By comparison, the center of the galaxy is about 8 kilo-parsecs away so we would get a decent range within our galaxy.
Supernovae can be amazingly bright.
Good job Danielle! Your answer of 1 Gpc is wayyy bigger than our galaxy :) 5/5
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