In 1929, astronomer Edwin Hubble discovered that almost all distant galaxies exhibit a positive
redshift. Furthermore, it appeared that the farther the galaxy, the larger its redshift. Here we
will rediscover Hubble’s Law using modern spectroscopic data and supernovae Ia as our distance
indicator to these galaxies. The data we will use come from the Sloan Digital Sky Survey (SDSS), a
project that aims to comprehensively map the universe. You can access the relevant data products
for this exercise at http://goo.gl/fmIvqc
Part A: Below is a list of supernovae observed between 2004 and 2007 and their positions in RA and Dec.
You can find the images and spectra of their host galaxies by entering their coordinates in the
respective fields. Explore the functions available, including magnifying the image, reading off
the photometric measurements (magnitudes in wavebands u, g, r, i, z) of your selected object,
and using the ‘Explore’ button to access more quantitative measurements for these objects. In
particular, familiarize yourself with the ‘interactive spectrum’ feature.
For each galaxy, we have a pretty extensive spectrum.
Part B: One of the features for determining distances to Type Ia supernovae is its peak absolute magnitude.
You explored the peak bolometric luminosities of SN Ia’s in Worksheet 7.1. The peak
V-band magnitude for SN Ia’s is about -19.3. Use the apparent peak magnitudes given in the
table above to calculate the distance of these supernovae in unit of Mpc.
To find distance, we can use our trusty distance formula :\[d = 10^{ \frac{m - M + 5}{5}} \] for each magnitude. The fourth galaxy did not have a spectrum associated with it, so we did not analyze it.
Part C: We can use the absorption or emission lines of the host galaxy to find their redshifts which,
as you found in Question 1), roughly equals the recessional velocity as a fraction of the speed
of light. To measure the redshift to each host galaxies, click on ‘Explore’ and then on the link
‘Interactive Spectrum’. Uncheck the boxes Best Fit and Mark Emission Lines. Zoom in on
the absorption line labeled Hα, and move your mouse over to the center of the line to read
the observed wavelength in Angstroms. The Hα has a rest (i.e. emitted) wavelength of 6563.0
Angstroms. Calculate the redshift, and then derive the radial velocity in kilometers per second,
using the relation z = v/c. How close does your redshift measurements compare to the one
SDSS reports in the table under the Interactive Spectrum link? Repeat for all the galaxies.
We found redshift and velocity using \[ \frac{ \lambda_{observed} - \lambda_{emitted}}{\lambda_{emitted}} = z \approx \frac{v}{c} \] to find:
We found redshift and velocity using \[ \frac{ \lambda_{observed} - \lambda_{emitted}}{\lambda_{emitted}} = z \approx \frac{v}{c} \] to find:
Result: \(H_0 = 68.816 \frac{km/s}{Mpc} \)
Part E: Write an equation for this line in the form of v = ___ D, where v is an object’s recessional velocity and D is the distance to that object. Express your Hubble Constant in terms of units km/s/Mpc. Congratulations, you have arrived at Hubble’s Law!
\[ v = 68.816 \frac{km/s}{Mpc} D \] Now we have a basic law of the universe (kinda) down!
Great job Danielle! 5/5
ReplyDelete