- A white dwarf can be considered a gravitationally bound system of massive particles.
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(a) Express the kinetic energy of a particle of mass m in terms of its momentum p instead of the
usual notation using its speed v.
- \[ \frac{1}{2}mv^2 = \frac{p^2}{2m} \]
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(b) What is the relationship between the total kinetic energy of the electrons that are supplying
the pressure in a white dwarf, and the total gravitational energy of the WD?
- We know \[ K = - \frac{1}{2} U \] and \[ U = \frac{GM^2}{r} \] and \[ K = \frac{p^2}{2 m_e} \] Combining these gives: \[ \frac{GM^2}{r} = \frac{p^2 N}{2m_e} \] Where \[ N = \frac{M_{\star}}{m_p + m_e} = \frac{M_{\star}}{m_p \left( 1 + \frac{m_e}{m_p} \right) } \approx \frac{M_{\star}}{m_p} \] So \[ \[ \frac{GM^2}{r} = \frac{p^2 M_{\star}}{2m_e m_p} \]
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(c) According to the Heisenberg uncertainty Principle, one cannot know both the momentum and
position of an election such that ∆p∆x > \(\frac{h}{4\pi} \) . Use this to express the relationship between the 4π kinetic energy of electrons and their number density ne (Hint: what is the relationship between an object’s kinetic energy and its momentum? From here, assume p = ∆p and then use the Uncertainty Principle to relate momentum to the volume occupied by an electron assuming Volume ~ (∆x)3.) \[ V \sim x^3 \sim n_e^{-1} \] \[ px = \frac{ h}{4 \pi} \] \[ p = \frac{h}{ 4 \pi x } = \frac{h n_e^{ \frac{1}{3}}}{4 \pi } \] For 1 electron \[ K = \frac{p^2}{2m_e} = \frac{h n_e^{\frac{2}{3}}}{32 \pi^2 m_e } \] For many \[ K = \frac{h^2 n_e^{\frac{2}{3}}}{32 \pi^2 m_e } \cdot \frac{M}{m_p} \]
- (d) Substitute back into your Virial energy statement. What is the relationship between ne and the mass M and radius R of a WD? \[ K = - \frac{1}{2} U \] \[\frac{h^2 n_e^{\frac{2}{3}}}{32 \pi^2 M_e } \cdot \frac{M}{m_p} = \frac{GM^2}{2r} \] \[ \frac{16M}{R} = \frac{h^2 n_e^{\frac{2}{3}}}{\pi^2 m_e m_p } \]
- (e) Now, aggressively yet carefully drop constants, and relate the mass and radius of a WD. \[ h^{\frac{2}{3}} = \frac{M}{R} \] Where \[ n = \frac{m}{V} = \frac{m}{\frac{4}{3} \pi R^3 }\] \[ \left( \frac{M}{R} \right)^{\frac{2}{3}} = \frac{M}{R} \] \[ R = \frac{1}{M^{\frac{1}{3}} } \]
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(f) What would happen to the radius of a white dwarf if you add mass to it?
- The relationship is inverted, so it would decrease.
UPDATE: I know my latex is not compiling in some places; I have no idea why. No matter how many different ways I type it, it won't compile (but just for some?). Do you have any suggestions? -
(a) Express the kinetic energy of a particle of mass m in terms of its momentum p instead of the
I worked with Barra, April, and Sean on this problem.
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