Part A: Inside the star, consider a mass shell of width ∆r, at a radius r. This mass shell has an energy density u + ∆u, and the next mass shell out (at radius r + ∆r) will have an energy density u. Both shells behave as blackbodies.
The net outwards flow of energy, L(r), must equal the total excess energy in the inner shell divided by the amount of time needed to cross the shell’s width ∆r. Use this to derive an expression for L(r) in terms of du/dr , the energy density profile. This is the diffusion equation describing the outward flow of energy.
Once again, an image from the textbook can help us visualize the situation.
We can simplify this because you know dEdu=4πr2dr
and drdt=v
and v=cρκΔr
L(r)=4πr2cρκdudr
Part B: From the diffusion equation, use the fact that the energy density of a blackbody is u(T(r)) = aT^4 to derive the differential equation: dT(r)dr∝−L(r)κρ(r)πr2acT3
where a is the radiation constant. You just derived the equation for radiative energy transport!
u(T(r))=aT4
du(T(r))=4aT3d(T(r))
From part a: du=L(r)ρκdr4πr2c
So L(r)ρκdr4πr2c=4aT3d(T(r))
Which simplifies to our answer! dT(r)dr∝−L(r)κρ(r)πr2acT3
Acknowledgements: I worked on this worksheet with Sean, April, and Barra.
Very nice....
ReplyDelete